How we worked it out
Updated as you change the numbers.
- Daily kWh = monthly use × 12 ÷ 365 × share covered. kW = daily kWh ÷ (sun hours × (1 − losses)). Panels = kW × 1,000 ÷ panel watts.
Method and assumptions
A 1 kW array produces about (peak sun hours × 1 kWh) a day, less system losses. NREL’s PVWatts tool models your exact location, tilt and shading and is the next step for a real quote.
Questions
How many solar panels for 900 kWh a month?
About 7.7 kW at 4.5 sun hours: 20 panels of 400 W.
Sources
Method and figures checked on . Every worked answer on this page is covered by an automated test. Found a mistake? Tell us.