How we worked it out
Updated as you change the numbers.
- τ = R × C. After τ the capacitor is at 63.2%; after 5τ, 99.3%. Cutoff f = 1 ÷ (2πRC).
Method and assumptions
The voltage on a charging capacitor is V(1 − e^(−t/τ)). The same RC pair forms a low- or high-pass filter with its −3 dB point at 1 ÷ (2πRC).
Questions
What is the time constant of 10 kΩ and 100 µF?
1 second; the cutoff frequency is 0.159 Hz.
Sources
Method and figures checked on . Every worked answer on this page is covered by an automated test. Found a mistake? Tell us.