How we worked it out
Updated as you change the numbers.
- vx = v cos θ, vy = v sin θ. Flight time t solves h + vy t − ½gt² = 0. Range = vx × t. Peak = h + vy² ÷ 2g.
Method and assumptions
With no air resistance and level ground, 45° gives the longest range.
Questions
How far does a ball launched at 20 m/s and 45° go?
About 40.8 m, peaking at 10.2 m.
Sources
Method and figures checked on . Every worked answer on this page is covered by an automated test. Found a mistake? Tell us.