GlenCalc

Percent yield calculator

Enter the limiting reactant, the product, and their coefficients in the balanced equation. For CaCO3 → CaO + CO2 both are 1.

Your answer

Theoretical yield5.6029 g
Percent yield89.24 %
Moles of reactant0.09991 mol
Moles of product expected0.09991 mol

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How we worked it out

Updated as you change the numbers.

  1. Moles of reactant = mass ÷ its molar mass.
  2. Moles of product = moles of reactant × product coefficient ÷ reactant coefficient.
  3. Theoretical yield = moles of product × its molar mass. Percent yield = actual ÷ theoretical × 100.

Method and assumptions

The limiting reactant is the one that runs out first; it alone sets the most product the reaction can make.

Questions

What is the theoretical yield of CaO from 10 g of CaCO3?

5.603 g. Getting 5 g is a percent yield of 89.2%.

Sources

Method and figures checked on . Every worked answer on this page is covered by an automated test. Found a mistake? Tell us.

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